Marxism moves fast.
June 11, 2009So today we moved on to A2 physics and the first topic was angular velocity. This is measured in S ^ -1 and is given by w(angular velocity) = 2pi/T .
T is defined as the time period for one revolution.
In a simplified view of Marxism, social revolutions pave the way to a perfect Marxist state. I’ve used the time period here to mean time period of one complete revolution, from the creation of the Russian Empire, to the Bolshevik Revolution in 1917.
The maths to work out the angular velocity of Marxism:
———————————————————————————————
T = Time period for one revolution
———————1721 – Treaty of Nystad (foundation of the Russian Empire)
7th November 1917 – October Revolution (November 7th = 311th day of the year)
196 years, 11 months, 7 days
1 minute = 60 s
1 hour = 3600 s
1 day = 24 (3600) s
1 year = 365(24(3600) s
T= (196 ( 365(24(3600)))) + (311(24(3600)))
= Time Period(s)
= 6.2079 * 10^9
angular velocity = 2pi/T
= 1.012123035 * 10^ -9 s ^ -1
= 1 * 10^ -9 (s^ -1)
This does not include leap years, no accurate date for the Treaty of Nystad is given and it’s a general fail, but Marxism moves scarily fast!
[...] Ok, I just discovered someone else’s blog on the topic – Angular Velocity of Marxism. I suspect this is the same person as it is verbatim to the one I found [...]
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